3 years ago

Please help. Stuck on it for a while

1 answer:

3 0

I assume you should set up an equation in y=mx+b form (but you use C(t) instead of y). m is your rate, b is your flat fee, and x is t.

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expeople1 [14]

The answer is (4x)-15.

5 0

4 years ago

garri49 [273]

I think you meant "y = 4 arccot (x)."

This is equivalent to:

y
---- = arccot x
4

and so cot (y/4) = x

8 0

3 years ago

postnew [5]

Differentiate g using the power rule:

$g'(x) = \dfrac34 x^{\frac34-1} - 2\cdot\dfrac14 x^{\frac14-1}$

$g'(x) = \dfrac34 x^{-\frac14} - \dfrac12 x^{-\frac34}$

$g'(x) = \dfrac14 x^{-\frac34} \left(3 x^{\frac12} - 2\right)$

$g'(x) = \dfrac{3\sqrt x - 2}{4 x^{\frac34}}$

The critical points of g occur where g' is zero or undefined.

We have

$g'(x) = 0 \implies 3\sqrt x - 2 = 0 \implies \sqrt x = \dfrac23 \implies \boxed{x = \dfrac49}$

and the derivative is undefined for

$\dfrac1{g'(x)} = 0 \implies 4x^{\frac34} = 0 \implies \boxed{x=0}$

8 0

3 years ago

MAXImum [283]

L=40×Tan45

=40

x²=root(40²-40²)

3 0

3 years ago

____ [38]

70$. 14 multipled by 5= 70

6 0

3 years ago