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3 years ago

Both cars start from the same point. Which describes the motion shown?

Physics

2 answers:

denis-greek [22]3 years ago

6 0

jane walks 4 blocks south while jeff walks 2 blocks east

evablogger [386]3 years ago

4 0

Is there a graph we can look at?

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Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm

faltersainse [42]

Answer:

1.35×10⁻⁷ m

37.278 mi/My

Explanation:

Speed of the tectonic plate= 6 cm/yr

Converting to seconds

$6=\frac{6}{365.25\times 24\times 60\times 60}$

So in one second it will move

$\frac{6}{365.25\times 24\times 60\times 60}$

In 71 seconds

$71\times \frac{6}{365.25\times 24\times 60\times 60}=1.35\times 10^{-5}\ cm$

The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m

Convert to mi/My

1 cm = 6.213×10⁻⁶ mi

1 M = 10⁶ years

$6\times 6.213\times 10^{-6}\times 10^6=37.278\ mi/My$

Speed of the tectonic plate is 37.278 mi/My

7 0

3 years ago

Which of the following traits might be considered an adaptation fora rabbit living in the Arctic?

puteri [66]

Where are the following traits ?

7 0

3 years ago

Read 2 more answers

1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground

Svetradugi [14.3K]

You have three known variables:

Acceleration - $9.8m/s^2$
Time - $1.85s$
Initial Velocity - $0m/s$

For the first part of your question:

$v = u + at

v = (0)+(9.8)(1.1)

v = 10.78 m/s v=11 m/s (2 significant figures)$

For the second part of your question:

$v=u+at

v=(0)+(9.8)(1.85)
v=18.13 m/s

$

This still needs to be converted to m/h:

$18.13m/s = 18.13\times 3600 metres/h=65628 metres/hour

65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h

= 41 mi/hr (2 significant figures)
$

5 0

3 years ago

Read 2 more answers

A stereo speaker produces a pure \"E\" tone, with a frequency of 329.6 Hz. What is the period of the sound wave produced by the

olya-2409 [2.1K]

Answer:

0.003034 s

1.035 m

4.5 m

Explanation:

$f$ = frequency of the tone = 329.6 Hz