1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
6

1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground

. Calculate the velocity in m/s after 1.10 seconds of freefall and calculate the velocity at impact in mi/hr.
Physics
2 answers:
kakasveta [241]3 years ago
7 0


what is the height of Fort Collins High School?

If found, use the formula, V=x/t-----------------(x=distance; t=time)

Svetradugi [14.3K]3 years ago
5 0
You have three known variables:

Acceleration - 9.8m/s^2
Time - 1.85s
Initial Velocity - 0m/s

For the first part of your question:

v = u + at

v = (0)+(9.8)(1.1)

v = 10.78 m/s  v=11 m/s (2 significant figures)

For the second part of your question:

v=u+at

v=(0)+(9.8)(1.85)
v=18.13 m/s



This still needs to be converted to m/h:

18.13m/s = 18.13\times 3600 metres/h=65628  metres/hour

65628 metres/hour = 65628\div1600 mi/h = 40.7925 mi/h

= 41 mi/hr (2 significant figures)





You might be interested in
14. Convert 22 degrees celsius to fahrenheit.<br> Please show your work
forsale [732]
(22°C × 9/5) + 32 = 71.6°F
6 0
3 years ago
Read 2 more answers
During their physics field trip to the amusement park, Leslie and Maria took a ride on the Whirligig. The Whirligig ride consist
grandymaker [24]

Answer:

a) frequency = 0.1724 Hz

b) Period = 5.8 sec

c) speed = 7.04 m/s

d) acceleration = 7.62 m/s²

Explanation:

Given that;

radius = 6.5m

time period = 5.8 sec every circle

a)  the frequency

frequency is the number of rotation in unit time

frequency = 1 / time period = 1/5.8

frequency = 0.1724 Hz

b)  the period

period is time taken in one rotation

period = total time / rotation = 5.8 / 1

Period = 5.8 sec

c)  the speed

speed = distance/time = circumference/time period = 2πr / t = (2π×6.5) / 5.8

speed = 7.04 m/s

d) acceleration

To find the acceleration we take the linear velocity squared divided by the radius of the circle.

so

acceleration = v² / r = (7.04)² / 6.5 = 49.5616 / 6.5

acceleration = 7.62 m/s²

6 0
3 years ago
Which of the following are steps for balancing chemical equations?
AveGali [126]

Answer:

C. Recheck the numbers of each atom on each side of the equation

to make sure the sides are equal.

D. Choose coefficients that will balance the equation

Explanation:

In balancing of chemical equation, the number of atoms on both sides must be equal in adherence to the law of conservation of mass.

Using the method of inspection, the equation is first observed to know the relationship between the combining atoms and the resulting ones.

After observing the reaction, put a coefficient that will balance the equation. Then recheck the number of each atom on both side of the equation. One can repeat the process till the equation is balanced.

5 0
3 years ago
Inertia is the resistance to change in motion so inertia depends solely on what
Alex Ar [27]
Inertia depends on mass, the more mass the more inertia.
6 0
3 years ago
calculate the time rate of change in air density during expiration. Assume that the lung has a total volume of 6000mL, the diame
kipiarov [429]

Answer:

The time rate of change in air density during expiration is 0.01003kg/m³-s

Explanation:

Given that,

Lung total capacity V = 6000mL = 6 × 10⁻³m³

Air density p = 1.225kg/m³

diameter of the trachea is 18mm = 0.018m

Velocity v = 20cm/s = 0.20m/s

dv /dt = -100mL/s (volume rate decrease)

= 10⁻⁴m³/s

Area for trachea =

\frac{\pi }{4} d^2\\= 0.785\times 0.018^2\\= 2.5434 \times10^-^4m^2

0 - p × Area for trachea =

\frac{d}{dt} (pv)=v\frac{ds}{dt} + p\frac{dv}{dt}

-1.225\times2.5434\times10^-^4\times0.20=6\times10^-^3\frac{ds}{dt} +1.225(-1\times10^-^4)

-1.225\times2.5434\times10^-^4\times0.20=6\times10^-^3\frac{ds}{dt} +1.225(-1\times10^-^4)

⇒-0.623133\times10^-^4+1.225\times10^-^4=6\times10^-^3\frac{ds}{dt}

           \frac{ds}{dt} = \frac{0.6018\times10^-^4}{6\times10^-^3} \\\\= 0.01003kg/m^3-s

ds/dt = 0.01003kg/m³-s

Thus, the time rate of change in air density during expiration is 0.01003kg/m³-s

3 0
3 years ago
Read 2 more answers
Other questions:
  • A planet has two
    7·1 answer
  • There are two balloons of charges +3.37 x 10-6 C and –8.21 x 10-6 C. The distance between the two balloons is 2.00 m. Determine
    13·1 answer
  • A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a un
    5·1 answer
  • After how many seconds does the motorcycle have positive acceleratolion​
    12·1 answer
  • Protons have electrical charge; electrons have. electrical charge
    15·1 answer
  • Which electromagnetic wave has the highest frequency​
    9·2 answers
  • A physicist wants to estimate the rate of emissions of alpha particles from a certain source. He counts 400 emissions in 80 seco
    12·1 answer
  • A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surf
    15·1 answer
  • Compare Earth’s, Venus’s, and Mars’s ability to sustain life.
    6·2 answers
  • A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n=1) interfere
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!