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aleksley [76]
3 years ago
11

How would I figure this out?

Mathematics
2 answers:
Rudiy273 years ago
8 0
Be doing 4x3 + 5x3 which is 15+12= 27
olasank [31]3 years ago
5 0
I think you will add all the number togerther
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Write the equation of the circle with a center at (- 2, - 8) and a radius of sqrt(10) .
Neporo4naja [7]

Answer:

(x + 2)^2 + (y + 8)^2 = 10

Step-by-step explanation:

The general equation of a circle with center at (h, k) and radius r

is (x - h)^2 + (y - k)^2 = r^2.  If the center is at (-2, -8) and the radius is √10, then this equation becomes:

(x + 2)^2 + (y + 8)^2 = 10

6 0
4 years ago
simplify the expression below. Express the simplified expression in standard form (12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)
joja [24]
<h3>Answer:   14s^4 - 7s^2 + 15</h3>

====================================================

Work Shown:

(12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)

12s^4-6s^2+4s+6s^4-4s+27-4s^4-s^2-12

(12s^4+6s^4-4s^4)+(-6s^2-s^2)+(4s-4s)+(27-12)

14s^4-7s^2+0s+15

14s^4-7s^2+15

Note: don't forget to distribute the negative to every term in the last parenthesis

3 0
3 years ago
jessa jane, and dina bought materials for thir project in math worth 306.75 pesos the girls divided the amount equally among the
Yuki888 [10]

Answer:

yeet

Step-by-step explanation:

ya dig

8 0
2 years ago
What is the equation of a line with a slope of -2 and passes through the point 3,5¿
dalvyx [7]
Y - y₁ = m(x - x₁)
y - 5 = -2(x - 3)
y - 5 = -2(x) + 2(3)
y - 5 = -2x + 6
  + 5          + 5
     y = -2x + 11
3 0
4 years ago
At what points are the equations y=x2 and y=1/x+2 equal?
Novay_Z [31]
Try this:
1) If y=x² and y=(2x+1)/x, then 
x^2= \frac{2x+1}{x}; \ \ \textless \ =\ \textgreater \  \ x^3-2x-1=0; \ (x \neq 0) <=>   (x+1)(x^2-x-1)=0; \ (x \neq 0)\ \ \textless \ =\ \textgreater \    \left[\begin{array}{ccc}x=-1\\x= \frac{1+ \sqrt{5} }{2} \\x= \frac{1- \sqrt{5}}{2} \end{array}\right
2) after 'x' are found it need to calculate 'y':
Answer: (-1;1), (-0.618;0.382), (1.618;2.618)
8 0
3 years ago
Read 2 more answers
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