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Art [367]
2 years ago
14

jessa jane, and dina bought materials for thir project in math worth 306.75 pesos the girls divided the amount equally among the

mselves. how much is each share?
Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0

Answer:

yeet

Step-by-step explanation:

ya dig

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Solve for x. Round to the nearest tenth, if necessary.
Sphinxa [80]

Answer:

2.8

Step-by-step explanation:

tan = opposite / adjacent

( opposite = side opposite of the angle and adjacent = side length that is not the opposite nor the hypotenuse ( longest side ) )

we are given an angle, ∠E = 26°

tanE = x / 5.7

tan26 = x / 5.7

==> multiply both sides by 5.7

5.7tan26 = x

==> simplify

x = 2.8 ( rounded )

3 0
2 years ago
For the graphed exponential equation, calculate the average rate of change from x = 0 to x = 1.
777dan777 [17]
The average rate of change is 4x
6 0
3 years ago
Read 2 more answers
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
Find the volume of the figure round your answer to the nearest tenth if necessary
egoroff_w [7]

Answer:

56.5

I think this is right

7 0
3 years ago
Paco's daughter will be participating in an upcoming dance recital. She will require a
docker41 [41]

Answer: The answer would be D, The number of dances paco's daughter plans to perform.

Step-by-step explanation:

3 0
3 years ago
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