Answer:
<h2>k = 13</h2>
Step-by-step explanation:
<h3>
</h3>
To solve first change the mixed number to an improper fraction
That's
<h3>
</h3><h3>
</h3>
So we now have
<h3>
</h3>
Move the fraction to the right side of the equation
That's
<h3>
</h3>
Since they have the same denominator we can add them directly
We have
<h3>
</h3>
we have the final answer as
<h3>k = 13</h3>
Hope this helps you
For starters, find the common change in the terms, in this case each goes down by 3. This lets you know you're gonna have a -3n in your equation as each term decreases by 3. Your equation should be in f(n)=c+rn form, with r being change in f(n), or -3 in this case. This gives you f(n)=c-3n. Now, solve for c, add 3n to both sides to get f(n)+3n=c. Plug in your n of 1 and f(n) of 20 to get c=20+3(1)=23. Plug in your c to your f(n) formula to get f(n)=23-3n as your f(n) function.
Answer:
<em>4</em><em>*</em><em>5x-7</em><em>=</em><em>20</em>
4*5(-7)-7=20
20(-7)-7=20
-140-7=20
-140=20+7
-140=27
=27+140
<u>=</u><u>167</u>
<em>-</em><em>3x</em><em>+</em><em>7</em><em>=</em><em>28</em>
-3(6)+7=28
-3(6)=28-7
-18=21
=21+18
<u>=</u><u>39</u>
<em>2x</em><em>+</em><em>3</em><em>=-7</em>
2(-5)+3=-7
2(-5)=-7-3
-10=-10
=-10+10
<u>=</u><u>0</u>
This is the concept of probability, we are required to calculate for the probability of rolling a 4 with a single die four times in a row;
To solve this we proceed as follows;
The probability space of a die is x={1,2,3,4,5,6}
The probability of a die falling on any of this number is:
P(x)=1/6
Thus the probability of rolling a 4 with a single die four times which makes up mutually exclusive events will be:
1/6*1/6*1/6*1/6
=(1/6)^4
=1/1296
The answer is B] 1/1296
