Solve the following system of equations. In other words, which values for x and y make both equations true?

1 answer:

3 0

I'm assuming the two equations are as follows:
y = 5x
7x + 2y = -17

You can substitute 5x for y in the second equation since they are equivalent. Remember that whatever you do to one side you must do to the other as well.
7x + 2y = -17
7x + 2(5x) = -17
7x + 10x = -17
17x = -17
17x /17 = -17 /17
x = -1

Now we sub in the value we have for x to find y:
y = 5x
y = 5(-1)
y = -5

We now check that both answers are right by substituting them both into the second equation:
7x + 2y = -17
7(-1) + 2(-5) = -17
-7 + (-10) = -17
-17 = -17

And it looks like it works! So x = -1, and y = -5. Hope this helps! :)

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\\ \quad \\
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% left side templates
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so if you notice yours $\bf \begin{array}{llll}
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&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
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now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
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