Let h = the number of horses in the field
Let c = number of cows in the field
There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)
There are 15 animals in the field. Therefore
h + c = 15 (2)
Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15
Answer:
The correct equation is
2h - 2 = 15
<span>lengths are in ratio 1:3
areas are in ratio
1 : 3</span>²<span> = 1: 9
area of ADG = 9 x 42 = 378 </span>
Answer: 79
Step-by-step explanation:
Given the following :
Graduation Rates:
Grade:82
Weight: 50%
Passing Rates:
Grade: 75
Weight: 30%
Enrollment Numbers:
Grade: 60
Weight: 10%
Career readiness:
Grade: 95
Weight: 10%
Overall score : Σ(grade × weight)
(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)
= (41 + 22.5 + 6 + 9.5)
= 79
Hence, overall score is 79
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
Answer:
3+4x
7-12
2x+14=18
four times a number
four times a number is added to seven
Step-by-step explanation:
