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3 years ago

Which operation should be performed first according to the order of operations?

1 answer:

3 0

You can start from any of the options mentioned above however make sure to follow the rule of BODMMAS but you can start from (D) 54÷3 if you just really want a section to start with

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Find the measurement of both complementary angles, if the measurement of the first one is 40° less than the measurement of the o

netineya [11]

90 - 40 = 50

Complementary angles add up to 90 degrees.

If one angle is 40 degrees less than the other, you just put it into an equation where 40 is subtracted from 90.

The answer would then be 50 degrees.

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=-x%20-3%20%5C%20%20%5Ctextless%20%5C%20%200" id="TexFormula1" title="-x -3 \ \textless \ 0"

VladimirAG [237]

- x < 3

Answer:
x < -3

8 0

2 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago

At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account

mario62 [17]

Answer:

Jamie should have reversed the inequality when using the division property of inequality.

Step-by-step explanation:

Jamie wrote

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x ≥ 10

Instead of reversing the inequality when using the division property of inequality

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x <or= 10

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=2%2B3%3D%3F" id="TexFormula1" title="2+3=?" alt="2+3=?" align="absmiddle" class="latex-formula

natka813 [3]

Answer:

$2 + 3 = 5$

Step-by-step explanation:

Thanks***

4 0

2 years ago

Read 2 more answers