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3 years ago

30 -60 -90 Please help.

Mathematics

2 answers:

marishachu [46]3 years ago

7 0

Answer:

-180

Step-by-step explanation:

Sophie [7]3 years ago

3 0

Shahahwhaha /// -180

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When the nth root of a is written, it is the positive value that is shown

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The nth root of a is always positive unless, a < 0 and "n" is an odd number. Also if a < 0 and "n" is an even number, then it's an imaginary number. I hope this helps a lot

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3 years ago

Let X have the uniform distribution U(0, 2) and let the conditional distribution of Y , given that X = x, be U(0, x). Find the j

Elina [12.6K]

Answer:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

Step-by-step explanation:

We have two random variables X and Y. $X \sim Unif(0,2)$ and given that X=x, Y has uniform distribution (0,x)

From the definition of the uniform distribution we have the densities for each random variable given by:

$f_X (x) =\frac{1}{2} , 0\leq x\leq 2$

$f_{Y|X} (y|x) = \frac{1}{x}, 0\leq y \leq x$

And on this case we can find the joint density with the following formula:

$f(x,y) = f_{Y|X}(y|x) f_X (x)$

And multiplying the densities we got this:

$f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x$

Now with the joint density we can find the expected value E(Y|x) with the following formula:

$E(Y|x) = \int y f_{Y|X}(y|x)dx$

And replacing we got:

$E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \$

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4 years ago

Evaluate the expression if a = -2, b= 7. and c= -3 ac + b=

zhannawk [14.2K]

Answer:

Step-by-step explanation:

plug in the numbers

-2(-3) + 7 = ?

6 + 7 = ?

Hope this helped! Have a nice day! Plz mark as brainliest!!!

-XxDeathshotxX

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3 years ago

Keira rented a car for 3 days. She paid $118 rent

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Answer:

389

Step-by-step explanation:

3*118 + 35

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3 years ago

Which expression is equivalent to %?

olganol [36]

Answer:

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Step-by-step explanation:

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⇒ $(x^{\frac{6}{3} })$

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3 years ago