Answer:Chemical reaction
Explanation:
The main concept that must be applied to determine the coefficients (amount of each item) is that there must be equal amounts of each element on each side of the equation. We are not destroying or creating new atoms. In this case, the unbalanced reaction formula is:
B
r
2
+
K
I
=
K
B
r
+
I
2
There are a two problems we need to solve before it will be balanced:
There are two moles of Iodine atoms (
I
) on the right side of the equation, while there is only one mole on the right side.
There are two moles of bromine (
B
r
) atoms on the left side, while there is only one on the right.
Since there are two moles of bromine atoms on the left side, we need two moles on the right as well. We can do this by adding a coefficient of two to the
'
K
B
r
'
term in the equation. Our now modified equation looks like this:
B
r
2
+
K
I
=
2
K
B
r
+
I
2
There is one mole of Iodine atoms on the left, and two on the right. To fix this, we add a coefficient of two to the
'
K
I
'
term. The resulting equation is below.
B
r
2
+
2
K
I
=
2
K
B
r
+
I
2
Bonus step: We can also put ones in front of the coefficient-less species. This is like changing a phrase from "an apple" to "1 apple". It is the exact same thing, but makes it a little more clear sometimes. This would like like this:
1
B
r
2
+
2
K
I
=
2
K
B
r
+
1
I
2
Can you see that there is now an equal amount of each element on each side of the equation? That means that it is balanced.
Answer:
If, for example, we want to know how many moles of oxygen will react with 17.6 mol ... Write the balanced chemical reaction for the combustion of C 5H 12
Explanation:
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C
Answer:
Algo importante sobre el balance de una reacción química es la ley de la conservación de la masa que establece que la masa no se crea ni se destruye sólo se transforma de modo que en una reacción química la suma de la masa de los reactivos debe ser igual a la suma de la masa de los productos.
Por ejemplo: La fermentación de la glucosa es una reacción química balanceada que da como resultado etanol y dióxido de carbono.
C₆H₁₂O₆ → 2C₂H₆O +2CO₂
Calculando la masa de los reactivos y productos, se debe cumplir la ley de la conservación de la masa:
C₆H₁₂O₆= 6*12+12*1+6*16=180 g/mol
C₂H₆O= 2*12+6*1+16=46 g/mol
CO₂=12+2*16=44 g/mol
C₆H₁₂O₆ → 2C₂H₆O + 2CO₂
180 g/mol = 2*46 g/mol + 2*44 g/mol
180 g/mol = 92 g/mol + 88 g/mol
180 g/mol = 180 g/mol
