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Answer:
The ratio of AC/CB=1/3
Step-by-step explanation:
We use the section formula:
We substitute the point A(-1.5,0) and B(4.5,8).
We plug in the points to get:
This is supposed to be equal to: (0,2).
We can equate, corresponding coordinates to find m and n.
This implies that:
Therefore the ratio is m:n=1:3
Answer:
21.27 meters.
Step-by-step explanation:
Please find the attachment.
Let H and h represent height of building and tree respectively.
We have been given that a person on the ground looks up at an angle of 28° and sees the top of a tree and the top of a building aligned. The tree is 20 m away from the person and the building is 60 m away from the person.
We know that tangent relates opposite side of a right triangle with its adjacent side.
Similarly, we can find height of the tree.
Therefore, the difference in heights between the building and tree is 21.27 meters.
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14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
, 
Final =
16)![\sqrt[3]{x^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E4%7D%20)
The power inside the root will be the numerator and root number will be the denominator
17)
× 
The numerator will be the power inside and the denominator will be the root number
![\sqrt[8]{x^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7Bx%5E3%7D%20)
14) The perimeter of this square is given as 28a²b⁴
The perimeter formula of a square is P = 4 x side
28a²b⁴ = 4s
7a²b⁴ = s
Area formula of a square is:
A = side²
= ( 7a²b⁴)²
= 49a⁴b⁸
15)
Let's deal with it one by one and combine at the end
Numerator = ( r²st³ )( 20r⁻³s⁻¹t⁻⁴ )
The product of power rule applies here
= ( 20r⁻¹t⁻¹ ) → { r²⁺⁽⁻³⁾s¹⁻¹t³⁺⁽⁻⁴⁾ }
Denominator = ( -4r⁻²t )³
The power of a product rule applies here
= ( -64r⁻⁶t³ ) → ((-4)³(r⁻²ˣ³)(t)³)
Combine =
Quotient of powers rule apply here
Lets separate again:
Final =
16)
The power inside the root will be the numerator and root number will be the denominator
17)
The numerator will be the power inside and the denominator will be the root number