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3 years ago

Select all the correct answers.

Mathematics

1 answer:

wel3 years ago

5 0

Eight of them wrong in just guessing so it’s probably wrong

You might be interested in

What is the gif of nine and fifty two

Novosadov [1.4K]

I assume you mean 9+52,
If so you can add the 9 and the 2 together:
9+2 = 11

Then you can add the 11 on to the 50 to get the final answer:
50+11 = 61

Hope this helps! :)

4 0

3 years ago

Write 50/6 as a mixed number. Give your answer in its simplest form.

DochEvi [55]

Answer:

8 1/3

Step-by-step explanation:

Step 1: Simplify

50/6 = 8 2/6

Step 2: Simplify fraction

2/6 = 1/3

Step 3: Add it up

8 1/3

5 0

3 years ago

Read 2 more answers

4. You sketch a right triangle that has a

stich3 [128]

Answer:

√95 cm

Step-by-step explanation:

To solve, you need to use the pythagorean theorem, or a^2 + b^2 = c^2

The hypotenuse is the c and let one leg be b. You can write:

a^2 + 7^2 = 12^2

a^2 + 49 = 144

Now, you need to solve for a:

a^2 = 144 - 49

a^2 = 95

a = √95 cm, or about 9.75cm

3 0

3 years ago

Read 2 more answers

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

Miguel runs 4 miles in 24 minutes.<br> How many miles does he run per minute?

vodomira [7]

Answer:

Miguel runs 1/6 miles per minute

Step-by-step explanation:

3 0

2 years ago