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Hunter-Best [27]
3 years ago
6

9. Predict the major products formed when: (a) Toluene is sulfonated. (c) Nitrobenzene is brominated. (b) Benzoic acid is nitrat

ed. (d) Isopropylbenzene reacts with acetyl chloride and AlCl3. If the major products would be a mixture of ortho and para isomers, you should so state.
Chemistry
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

a) ortho-para isomers predominates

b) 3-nitrobenzoic acid ( meta isomer predominates)

c) 3-bromo nitrobenzene ( meta isomer predominates)

d) the ortho- para isomers predominates

Explanation:

a) Toluene contains -CH3 which is an ortho- para- director hence the major product of the sulphonation of toluene should be the ortho- para isomers.

b) The major product of the nitration of benzoic acid is 3-nitrobenzoic acid. This is an electrophilic substitution in which the meta isomer predominates.

c) The meta isomer predominates giving 3-bromo nitrobenzene as the major product.

d) The isopropyl group is an ortho- para director hence the ortho- para isomers predominates .

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Answer:

when we drink the milk the digestive system produce protease enzyme to break down the protein of milk.

7 0
3 years ago
Question 7 (5 points)
Serggg [28]

Answ  Es la B .

Explanation

By raising the temperature of a liquid, it turns into a gas, therefore its particles will have more movement and its kinetic energy will increase. the more you raise the temperature, the more space they will have between the molecules.

4 0
3 years ago
The air pressure for a certain tire is 109 kPa. What is this pressure in atmospheres?​
Len [333]

1.08 atm is the pressure for a certain tire in atmosphere.

<u>Explanation:</u>

One kilo pascal (1 kPa) corresponds to 1000 pascal. Another common unit used for pressure is atmosphere (symbolised as ‘atm’). 1 atm refers the standard atmospheric pressures and corresponds to 760 mm Hg and 101.3 kPa. Atmospheric pressures are commonly referred as square inches (psi)/ pounds.

  1 \mathrm{atm}=101.3 \mathrm{kPa}=101,325 \mathrm{Pa}=760 \mathrm{mm} \mathrm{Hg}=760 \text { torr }=14.7 \mathrm{lb} / \mathrm{in}^{2}(\mathrm{psi})

Given:

The air pressure for a certain tire = 109 kPa

We need to find pressure in atmospheres

So, we know,

1 atm = 101.3 kPa

Hence,

\frac{109 \mathrm{kPa}}{1} \times \frac{1 \mathrm{atm}}{101.3 \mathrm{kPa}}=1.076=1.08 \mathrm{atm}

1.08 atm is the pressure for a certain tire in atmosphere.

3 0
4 years ago
Select the correct answer.
sergey [27]
I believe the correct answer is B
8 0
3 years ago
A certain shade of blue has a frequency of 7.18 × 1014 Hz. What is the energy of exactly one photon of this light?
AysviL [449]
I'm assuming you meant 10^(14) instead of 1014
if so, then the energy of one photon will be be 4.76×10^(-19) Joules

4 0
3 years ago
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