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Mamont248 [21]
3 years ago
13

Difference between : orbit in Bohr model, and, orbital in Quantum model

Chemistry
1 answer:
Mamont248 [21]3 years ago
8 0
Bohr display says obviously the electron spins around the core in orbit. so circle implies a circular locale around core.
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Explain how a Buffer acts to resist pH change in a system upon addition of an acid or a base
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Answer:

Explanation has been given below.

Explanation:

  • A buffer consists of either of a weak acid along with it's conjugate base or a weak base along with it's conjugate acid.
  • Let's consider a buffer consists of a weak acid along with it's conjugate base
  • If we add an acid to this buffer then conjugate base gets protonated and converted to corresponding weak acid. So effect of addition of acid gets neutralized by forming weak acid rather than increase in concentration of proton in solution.
  • If we add a base to this buffer then weak acid gets converted to corresponding conjugate base. So effect of addition of base gets neutralized by forming conjugate base rather than in crease in concentration of hydroxyl ion in solution.
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(a) How many stereoisomers are possible for 4,4-dimethyl-1,2-cyclopentanediol?
Monica [59]

Answer:

(a) 4 stereoisomers: (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. (b) (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol (c) No, they are optically inactive.

Explanation:

(a) The stereoisomers possible for 4,4-dimethyl-1, 2-cyclopentanediol are (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. Their structures are shown in the attached file.

(b) The oxidation reaction that occurs between 4,4-dimethylcyclopentene and osmium tetroxide produces (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol. Their structures are also shown in the attached file.

(c) The products of the oxidation reaction in (b) are optically inactive because the compounds contain plane of symmetry that makes them optically inactive compound.

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5 0
4 years ago
The discovery of the electron as a subatomic particle was a result of
liberstina [14]

The discovery of the electron as a subatomic particle was a result of English physicist J.J. Thomson

5 0
3 years ago
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If 2.4x105L of gas is at 180mmHg, what is the pressure when the gas is
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Thats the solution to the question

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