Answer:
The speed of a spound wave in this water is 1484.1 m/s
Explanation:
Step 1: Data given
Frequency = 349.2 Hz
Wavelength = 4.25 m
Step 2: Calculate the speed
v = f*λ
⇒ with v= the speed of a sound wave in this water
⇒ with f = the frequency = 349.2 Hz
⇒ with λ = the wavelength = 4.25 m
v = 349.2 Hz * 4.25 m = 1484.1 m/s
The speed of a spound wave in this water is 1484.1 m/s
<span>THE HIGHEST CONCENTRATION OF HYDROGEN IONS IS LOCATED IN THE INTER-MEMBRANE SPACE. HYDROGEN IONS REACH THE INTER-MEMBRANE SPACE THROUGH PROTEIN CHANNELS EMBEDDED IN THE MITOCHONDRIAL MEMBRANE. THE MAIN FUNCTION OF INTER MEMBRANEIS OXIDATIVE PHOSPHORLATON. ENERGY IS REQUIRED TO MOVE THE HYDROGEN IONS ACROSS THE MEMBRANE BECAUSE THE HYDROGEN IONS ARE MOVING AGAINST THE CONCENTRATION GRADIENT. H+ GOES AGAINST THE CONCENTRATION GRADIENT THE USE OF THE GRADIENT TO DRIVE ATP SYNTHASE. HYDOGEN IONS DRIVE ATP SYNTHASE IN PHTOSYNTHESIS. THIS HAPPENS WHEN HYDROGEN IONS GET PUSHED ACROSS THE MEMBRANE CREATING A HIGH CONCENTRATION INSIDE THE THYLAKOID.</span>
The amino acid for this should be Arginine. I am not entirely sure.
Answer: A. ![[H_3O^+]=0.64\times 10^{-7}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D0.64%5Ctimes%2010%5E%7B-7%7DM)
B. ![[OH^-]=0.11\times 10^{-5}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.11%5Ctimes%2010%5E%7B-5%7DM)
C. ![[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B0.000775%7D%3D1.3%5Ctimes%2010%5E%7B-11%7DM)
Thus solution B is basic in nature.
Explanation:
pH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
pH for acidic solutions is less than 7, for basic solutions it is more than 7 and for neutral solutions it is equal to 7.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![pOH=-log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E-%5D)
or ![[H^+][OH^-]=10^{-14}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%5BOH%5E-%5D%3D10%5E%7B-14%7D)
A. ![[OH^-]=1.55\times 10^{-7}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.55%5Ctimes%2010%5E%7B-7%7DM)
![[H_3O^+]=\frac{10^{-14}}{1.55\times 10^{-7}}=0.64\times 10^{-7}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B1.55%5Ctimes%2010%5E%7B-7%7D%7D%3D0.64%5Ctimes%2010%5E%7B-7%7DM)
![pH=-log[H_3O^+]=-log[0.64\times 10^{-7}]=7](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D%3D-log%5B0.64%5Ctimes%2010%5E%7B-7%7D%5D%3D7)
B. ![[H_3O^+]=9.43\times 10^{-9}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D9.43%5Ctimes%2010%5E%7B-9%7DM)
![[OH^-]=\frac{10^{-14}}{9.43\times 10^{-9}}=0.11\times 10^{-5}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7B9.43%5Ctimes%2010%5E%7B-9%7D%7D%3D0.11%5Ctimes%2010%5E%7B-5%7DM)
![pH=-log[H_3O^+]=-log[9.43\times 10^{-9}]=8](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D%3D-log%5B9.43%5Ctimes%2010%5E%7B-9%7D%5D%3D8)
C. ![[H_3O^+]=0.000775M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D0.000775M)
![pH=-log[H_3O^+]=-log[0.000775]=3](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D%3D-log%5B0.000775%5D%3D3)
Thus solution B is basic.
Answer:
2
Explanation:
#1 is incorrect as there is no upward force that would balance the 5 N downward force
#3 is incorrect 2 is less than 5 = net force downward of 3 N
#4 is incorrect 5 is greater than three = 2 N net force going to the left and 2N going up
