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Aleksandr-060686 [28]
2 years ago
14

Express the ratio below in its simplest form.1:1.5​

Mathematics
2 answers:
Soloha48 [4]2 years ago
6 0

Answer:

that is the simplest form

Step-by-step explanation:

Anestetic [448]2 years ago
5 0

Answer:

That is the simpilist form

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An item is regularly priced at $45. Josh bought it on sale for 15% off the regular price.
Mariulka [41]

15/100=x/45

675=100x

6.75=x

5 0
2 years ago
A state trooper temp track of the number of speeding ticket he gave out each week over the course of seven weeks in the table be
NikAS [45]

Answer:

B: The center of data is shown by the mean, which is 43.

Step-by-step explanation:

Add up all the digits (33+38+38+40+44+51+57)/7=43 the mean. The mean is always teh center of data so it's B. Hope this helps.

3 0
3 years ago
Which number is NOT in the solution set of the inequality x>-15?
Ipatiy [6.2K]

Answer:

d

Step-by-step explanation:

if x has to be greater than -15 and -20 = x than its not true because -20 isn't greater than -15

5 0
3 years ago
Read 2 more answers
37.33 as a percentage of 56​
nika2105 [10]

Answer:

20.9048

Step-by-step explanation:

37.33% of 56 = 0.3733 × 56 = 20.9048

i hope this is what you meant. 37.33% of 56 is 20.9048

4 0
2 years ago
Read 2 more answers
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
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