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3 years ago

Find the equation of the line that contains the points (2,-5) and (-3,10)

1 answer:

Natasha2012 [34]3 years ago

3 0

Let’s just use the first point you gave, (2, -5), since only one equation fits it. We can plug the x value, 2. Into each equation to find y, and see if it matches our point. If we plug 2 into A, y is equal to -5, which matches our point.

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Suppose the length of each side of a square is increased by 5 feet.if the perimeter of the square is now 56 feet.what were the o

skelet666 [1.2K]

We can find the length of the sides now by dividing 56 by 4, which gives us 19. Subtracting 5 from 19 gives us our answer of 14 feet.

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3 years ago

Please help me :( with this

hodyreva [135]

Answer:

Step-by-step explanation:

Similar triangles. MNL is just ABC but 3/4 the size.

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3 years ago

Please help me ASAP :)

Ulleksa [173]

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3 years ago

Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)

Lyrx [107]

Answer:

The equation of the line is,

$y = - \frac{2}{5} x - 1$

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

$2x + 5y = 15$

$5y = 15 - 2x$

$y = 3 - \frac{2}{5} x$

$y = - \frac{2}{3} x + 5$

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

$y = - \frac{ 2}{5}x + b$

$let \: x = - 10,y = 3$

$3 = - \frac{2}{5} ( - 10) + b$

$3 = 4 + b$

$3 - 4 = b$

$b = - 1$

3 0

3 years ago

Read 2 more answers

Write an equation in point slope and slope intercept form of a line that passes through the given point and has the given slope

Evgesh-ka [11]

Answer:

Point-Slope: $y+4=-\frac{1}{2}(x+3)$

Slope-Intercept: $y=-\frac{1}{2}x-\frac{11}{2}$

Step-by-step explanation:

The point-slope formula is $y-y_{1}=m(x-x_{1} )$ . The slope-intercept formula is $y=mx+b$ . Since we are given the point and slope, we can directly plug it into the point-slope formula.