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Dimas [21]
3 years ago
14

Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2

x) = 10 x − 10 + 4x = 10 5x − 10 = 10 5x = 0 x = 0 2(0) + y = 5 y = 5 He should have substituted 5 + 2x He combined like terms incorrectly, it should have been 4x instead of 5x He subtracted 10 from the right side instead of adding 10 to the right side He made no mistake
Mathematics
1 answer:
patriot [66]3 years ago
6 0
The correct answer is "He did not distribute correctly". The correct incomplete-worked expression is x - 10 + 4x = 10

I hope this helps!
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X + (2x + 5) = 3(x – 4)+7
eduard

Answer:

Not true

Step-by-step explanation:

x + (2x + 5) = 3(x – 4)+7

Opening bracket on left and side and distributing 3 over (x-4) on right hand side

x+2x+5=3x-3 x 4 + 7

adding like terms

3x+5=3x-12+7

3x+5=3x-5

Hence

5 = -5

Which is not possible , Hence the equation given to us is false.

5 0
3 years ago
Shelly is trying to improve her running time for a track race she ran the first race in 43.13 seconds her time was 43.1 seconds
lesantik [10]
I we consider her running times as an arithmetic series with common difference:
43.13 - 43.1 = -.03/2 = -.015, Shelly's time in the fourth race will be 43.1 - .015 = 43.085.
7 0
3 years ago
Read 2 more answers
Louise, Tammy, Delores, and Sheryl score 78 points total in the tennis matches they play. They score a consecutive number of poi
irga5000 [103]

\huge\boxed{18\ \text{points}}

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with x, x+1, x+2, and x+3 respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to 78.

x+x+1+x+2+x+3=78

Now, simplify.

4x+6=78

Subtract 6 on both sides.

\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}

Divide both sides by 4.

\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}

Since Louise's score is x, the answer is 18.

<h3>Double-checking</h3>

To verify our answer, add the point totals 18, 19, 20, and 21.

This equals 78, so we can be sure the answer is correct.

5 0
1 year ago
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
3 years ago
A manufacturer makes ball bearings out of molten steel. It takes 5.24 cubic centimeters of molten steel to make ? ball bearings
sammy [17]
<span>So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel</span>
8 0
2 years ago
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