Question

Which of the following is equivalent to (p3)(2p2 - 4p)(3p2 - 1)?

Answer 1

(p³)(2p² - 4p)(3p² - 1) = (p³)(2p²*3p² - 4p*3p² - 1*2p² - 4p*(-1)) = 
= (p³)(6p⁴ - 12p³ - 2p² + 4p) 

Answer: A)

Answer 2

Answer:  Option 'A' is correct.

Step-by-step explanation:

Since we have given that

$(p^3)(2p^2-4p)(3p^2-1)$

Now, we will solve the last two terms using "Product of polynomials":

$\left(2p^2-4p\right)\left(3p^2-1\right)\\\\\text{Using this :}\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd\\\\a=2p^2,\:b=-4p,\:c=3p^2,\:d=-1\\\\=2p^2\cdot \:3p^2+2p^2\left(-1\right)+\left(-4p\right)\cdot \:3p^2+\left(-4p\right)\left(-1\right)$

So, at last it becomes:

$\left(p^3\right)\left(6p^4-12p^3-2p^2+4p\right)$

Hence, Option 'A' is correct.