The expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
<h3>How to write the
expression as a sum or difference of
logarithm?</h3>
The expression is given as:
log [x^3 square root x 1/(x-2)^2
Rewrite properly as:
log [x^3 √x + 1/(x-2)^2]
Express the above expression as products and quotients
log [x^3 * √x + 1/(x-2)^2]
Apply the product and quotient of logarithm
log(x^3) + log(√x + 1) - log(x - 2)^2
Rewrite as:
log(x^3) + log(√x + 1) - 2log(x - 2)
Hence, the expression as a sum or difference of logarithm is log(x^3) + log(√x + 1) - 2log(x - 2)
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Answer:
Step-by-step explanation:
The expression is for the interior angle of the hexagon; one interior angle is equal to 
.
Since an interior angle of a hexagon measures 120°, we have the equality
.
Now it is just a matter of solving for 
Answer:
a. .15 b. 5.40
Step-by-step explanation:
Hi! The first thing you want to do is find the unit rate, which would be 9 divided by 60. This should be 15 cents per hour. Next, for the second part, you multiply by 36, which should be $5.40. Hope this helps!
Answer: -2x - 10
Steps: -2(x+5)
Apply the distributive law [ a(b + c) = ab + ac ]:
a = -2, b = x, c = 5
-2x + (-2) × 5
Apply minus/plus rules: -2x - 2 × 5
Multiply the numbers: 2 × 5 = 10
-2x - 10
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