answer = the elder bother is 17 and the younger one is 15
constructive odd integers= 15 and 17
17×15= 255
255+38 = 293
Square root of 293 = 17
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
2/15
Step-by-step explanation:
Answer:
no se de que hablas
Step-by-step explanation:
hablas español o no
Since FA || BE, then angle 1 must equal angle 2 since they are corresponding angles along parallel lines where the transverse line cuts.
Thus, if angle 1 is 59, then angle 2 must also be 59 (ie D)
