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masha68 [24]
4 years ago
10

Making a career decision is simple, and it's not necessary to use a process. true or fralse

Mathematics
1 answer:
tino4ka555 [31]4 years ago
8 0
Making a career decision is simple but important task. And a proper process needs to be followed. By a process, we can say choosing the subject interest, finding the career options in your interest area, figuring out the college and the cost of education. And most important working with patience and honesty is the fundamental to reach a zenith in your career.
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HELP FIND THE UNIT RATE OF 90 DAYS/20 TRIPS PLEASEEEEE
iris [78.8K]

Answer:

The unit rate is 4.5 days per trip

Step-by-step explanation:

So the equation would be 90 divided by 20

Simplified it is the same thing as 9 divided by 2

90 divided by 20 is 4.5

8 0
3 years ago
Read 2 more answers
Use the graph to the right to write an equation of the line. What is the equation?​
Bingel [31]

Answer:

y = 1/4 x - 2

Step-by-step explanation:

To write the equation of a line, find from the line the slope and y-intercept. The y-intercept is where the line crosses the y-axis which here is at point (0,-2).

The slope of the line is found by writing a ratio between the vertical distance and the horizontal distance between points.

Slope is 1/4.

Substitute m = 1/4 and b = -2 into the slope intercept form y = mx + b.

y = 1/4 x - 2

5 0
3 years ago
All Parent functions have both x- intercepts and y-intercepts EXCEPT. I. Linear II. Absolute Value III.Quadratic IV. Cubic V.Squ
stealth61 [152]

Answer:

Reciprocal, Exponential and Logarithmic.

Step-by-step explanation:

x intercept is the value of x where y value is 0.

y intercept is the value of y where x value is 0.

Let us have a look at the possibility for <em>each parent function </em>as given.

I. Linear

y =x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

II. Absolute value

y =|x|

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

III. Quadratic

y =x^{2}

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

IV. Cubic

y =x^3

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

V. Square root

y =\sqrt x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VI. Cube root

y =\sqrt[3]x

When x = 0, y = 0 and

When y = 0, x = 0

Therefore, both x and y intercept exist.

VII. Reciprocal

y =\dfrac{1}x

When x = 0, y \rightarrow \infty

Therefore, both x and y intercept do not exist.

VIII. Exponential

y =b^x

where b is any base:

When x = 0, y =1 therefore y intercept exists.

When we put y = 0, which is not possible

Therefore, both x and y intercept do not exist.

IX. Logarithmic

y =logx

When x = 0, y \rightarrow not defined

Therefore, both x and y intercept do not exist.

6 0
3 years ago
Expand (3x+8)^2<br><br> If necessary, combine like terms
morpeh [17]
(3x+8)(3x+8)=
9x^2+24x+24x+64=
9x^2+48x+64
8 0
3 years ago
Read 2 more answers
What is the positive solution to the equation 64x2 + 12x = 1.
Inga [223]

Answer:

1/16

Step-by-step explanation:

Here: 64x^2+12x = 1

Then, 64x^2 +12x -1=0

The delta = 12^2 - 4*64*(-1)= 400 = 20^2

These two solutions are:

(-12+20)/(2*64)=  8/(2*8*8)= 1/16

(-12-20)/(2*64) but this is negatif.

1/16 is the positif solution.

Hope that useful for you.

3 0
3 years ago
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