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3 years ago

Is 3/4 bigger than 11/16?

1 answer:

5 0

Yes because if you simplify 11/16 you would not get 3/4. Or a bwtter way is if you times 4 by 4 to get 16 as a denominator, then multiply 3 by 4 it equals more than 11/16.

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Find an equation of the circle that satisfies the given conditions.

hodyreva [135]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the centre
r - the radius

The midpoint of the diameter is the centre of a circle.
The coordinates of the midpoint:
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$
(x₁,y₁), (x₂,y₂) - the coordinates of endpoints

$P(-1,1) \\
x_1=-1 \\ y_1=1 \\ \\ Q(5,9) \\ x_2=5 \\ y_2=9 \\ \\
\frac{x_1+x_2}{2}=\frac{-1+5}{2}=\frac{4}{2}=2 \\ \frac{y_1+y_2}{2}=\frac{1+9}{2}=\frac{10}{2}=5$

The centre of the circle is (2,5).

The radius is the distance between an endpoint of the diameter and the centre.
The formula for distance:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-1,1) \\ x_1=-1 \\ y_1=1 \\ \\ (2,5) \\ x_2=2 \\ y_2=5 \\ \\ d=\sqrt{(2-(-1))^2+(5-1)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

The radius is 5.

$(x-2)^2+(y-5)^2=5^2 \\
\boxed{(x-2)^2+(y-5)^2=25}$

4 0

3 years ago

What is the volume of this solid? Recall the formula V = Bh.

Viktor [21]

Answer:

280

Step-by-step explanation:

V=Bh

V=1/2(7x10)8 *it is a triangluar pyrmid so the base is a triangle*

V=1/2x70x8

V=35x8

V=280

Answer:280

5 0

3 years ago

Read 2 more answers

A polynomial has zeros x=0, x= -3, X = 4. What are some possible factored equations for this fourth degree polynomial.

kati45 [8]

Answer:

$x^{2} (x + 3)(x - 4)$

Step-by-step explanation:

You can multiply this out to get the full equations.

It's to the 4th degree so the x on the outside has to be squared to add the fourth degree.

To get other zeros:

x + 3 = 0

x = -3

x - 4 = 0

x = 4

Hope this helped. :0)

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%20%20%5Cfrac%7B2%7D%7B9%7D%20%29%28x%20%2B%20%20%5Cfrac%7B1%7D%7B2%7

Aleonysh [2.5K]

$f(x) = (x - \dfrac{2}{9} )(x + \dfrac{1}{2} )$

$\text {When } f(x) = 0 :$

$(x - \dfrac{2}{9} )(x + \dfrac{1}{2} ) = 0$

$(x - \dfrac{2}{9} ) = 0 \text { or } (x + \dfrac{1}{2} ) = 0$

$x = \dfrac{2}{9} \text { or } x = -\dfrac{1}{2}$

3 0

4 years ago

How to write 1.075 in two foarms

tangare [24]

1 75/1000

One and seven thousandth

7 0

3 years ago

Read 2 more answers