if she has 9, add 7. you have 16. divide it by half, 8. subtract 3 and you get 5.
I think the value of x is 15
Answer:
1, 4, 3, 6, 2, 7, 5
Step-by-step explanation:
The circle operator in
means that the function named on the left (f) operates on the result of the function named on the right (g). So, the notation
![(f\circ g)(x)](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29)
means
![f(g(x))](https://tex.z-dn.net/?f=f%28g%28x%29%29)
That is, g(x) is computed and used as input to the function f. When the function definitions are as shown, the evaluation proceeds in these steps.
![(f\circ g)(-4)\\\\=f(g(-4))\quad\text{write as function of a function}\\\\=f(-2(-4)^2)\quad\text{put -4 for x in $g(x)$}\\\\=f(-2(16))\quad\text{evaluate $(-4)^2$}\\\\=f(-32)\quad\text{evaluate $g(-4)$}\\\\=2(-32-1)\quad\text{put -32 for x in $f(x)$}\\\\=2(-33)\quad\text{first step evaluating $f(-32)$}\\\\=-66\quad\text{value of $(f\circ g)(-4)$}](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28-4%29%5C%5C%5C%5C%3Df%28g%28-4%29%29%5Cquad%5Ctext%7Bwrite%20as%20function%20of%20a%20function%7D%5C%5C%5C%5C%3Df%28-2%28-4%29%5E2%29%5Cquad%5Ctext%7Bput%20-4%20for%20x%20in%20%24g%28x%29%24%7D%5C%5C%5C%5C%3Df%28-2%2816%29%29%5Cquad%5Ctext%7Bevaluate%20%24%28-4%29%5E2%24%7D%5C%5C%5C%5C%3Df%28-32%29%5Cquad%5Ctext%7Bevaluate%20%24g%28-4%29%24%7D%5C%5C%5C%5C%3D2%28-32-1%29%5Cquad%5Ctext%7Bput%20-32%20for%20x%20in%20%24f%28x%29%24%7D%5C%5C%5C%5C%3D2%28-33%29%5Cquad%5Ctext%7Bfirst%20step%20evaluating%20%24f%28-32%29%24%7D%5C%5C%5C%5C%3D-66%5Cquad%5Ctext%7Bvalue%20of%20%24%28f%5Ccirc%20g%29%28-4%29%24%7D)
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If your step choices at the bottom are numbered 1 to 7 left-to right, then the sequence is as shown in the Answer section above.
Basically anything greater than zero...k>0