The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J
The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.
However, since we are required to determine heat released when the helium gas condenses.
The heat of condensation per gram is; -21 J/g.
Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.
Approximately, -250J.
Read more on latent heat:
brainly.com/question/19863536
Answer: question 1: 20 question 2: 21 question 3: 17, 19, 23
Step-by-step explanation:
This is an linear equation, so
y=mx + b
m= money w=weeks
m= -20w +200
Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by (
):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level : 
Two-tailed T-value for df = 63 and
would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Answer:
The answer is 66.6346 round it to what ever place you need to.
Step-by-step explanation:
Take the 56,47, multiply it by .18, and add that value to 56.47 Hope it helps