Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
= 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
= 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
= 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
= 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
= 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.
Answer:
√841
Step-by-step explanation:
You would use pythagorean theorem to solve this problem:
a² + b² = c²
a = 20 b = 21
20² + 21² = 400 + 441 = 841
√841
<u>Answer</u>
c. buying it at a 10 percent discount without sales tax.
<u>Explanation</u>
We are going to compare the 3 choices and then determine the most cost effective.
<em>a. using a paid membership card to buy it at a 10 percent discount.</em>
10% of $100 = 10/100×100 = $10
cost = $100 - $10 = $90
On top of this $90 there is the charges of the membership card.
<em> b. buying it online at a 10 percent discount with a $5 shipping charge.</em>
100%-10% = 90%
90% of 100 = $90
Cost: $90 + $5 = $95
<em>c. buying it at a 10 percent discount without sales tax.</em>
100% - 10% = 90%
90/100 × 100 = $90. This is the must cost effective method since there is no other cost involved.
Ask your teacher for help or watch a video that would help or do research and study
Answer:
refer to explanation
Step-by-step explanation:
the lengths of the base and height are the factors of 20
so they can be 5×4, 10×2, 1×20
