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3 years ago

Solve for r r=c/2π c=15

1 answer:

4 0

<span>In getting the value of R in the formula of the circumference that you give where as the circumference is equals to 15, the derived formula is R=C/2pi and the answer would be that R is equals to 2.39. I hope you are satisfied with my answer and feel free to ask for more if you have more questions and further clarifications </span>

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

2 years ago

Plz help! I need at least 2 answers

klemol [59]

Answer:

I can't see the side lengths so I can't answer it

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Write √3 x √6 in the form b√2 where b is an integer

bagirrra123 [75]

Answer:

3√2

Step-by-step explanation:

√3 x √6

= √3×6

= √18

= √9×2

= √9 × √2

= 3 × √2

= 3√2

I hope this was helpful, please rate as brainliest

7 0

3 years ago

My number is a multiple of 2 & 7 my number is less than 100 but greater than 50 my number is the product of three prime numb

forsale [732]

12345678910
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8 0

2 years ago

Which expression is equivalent to the one in the picture?

Ne4ueva [31]

Answer:

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

$\sqrt[n]{a^{m}}=a^{\frac{m}{n}}$

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

$\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}$

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, $\sqrt[4]{16}$ = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

$2x^{\frac{15}{4}}y^{\frac{17}{4}}$

5 0

3 years ago