Answer:
Let the side of one square be x. Area = x*x = x²
Then the side of other square would be 2x , Area = 2x*2x = 4x²
Combined area = x² + 4x² = 5x²
This combined area = 45 cm²
you simplify
Therefore 5x² = 45 Divide both sides by 5
x² = 45/5
x² = 9 Take square root of both sides
x = √9
x = 3
Length of larger square is 2x = 2*3 = 6 cm
Length of larger square = 6cm
Step-by-step explanation:
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
When x=1/4 x²=1/16 so f(1/4)=y=2 1/16 last answer
I don't know what your asking
A: an exterior angle is supplementary to the adjacent interior angle.
