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vesna_86 [32]
3 years ago
14

Find the x- and y-intercept of the line. 5x – 4y = 40

Mathematics
1 answer:
MariettaO [177]3 years ago
5 0
The x-intercept is 8
the y-intercept is -10
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the combined area of two squares is 45 square centimetres each side is twice as long as a side of the other square what length o
Ostrovityanka [42]

Answer:

Let the side of  one square be x.    Area = x*x = x²

Then the side of other square  would be 2x ,   Area = 2x*2x = 4x²

Combined area = x² + 4x²  = 5x²

This combined area = 45 cm²

you simplify

Therefore  5x²  = 45   Divide both sides by 5

                 x²  =  45/5

                 x²  = 9        Take square root of both sides

                 x   =  √9

                 x  = 3

Length of larger square is 2x  = 2*3 = 6 cm

Length of larger square = 6cm

Step-by-step explanation:

4 0
3 years ago
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2
Oksanka [162]

If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width

Solution:

Let the length of rectangle=x

Width of rectangle=x/10

Perimeter is 2(Length+Width)

= 2(x+x/10)

Area of Rectangle= Length* Width=x*x/10

As, Perimeter=2(Area)

So,2(x+x/10)=2(x*x/10)

Multiplying the equation with 10, we get,

2(10x+x)=2x²

Adding Like terms, 10x+x=11x

2(11x)=2x^2

22x=2x²

2x²-22x=0

2x(x-11)=0

By Zero Product property, either x=0

or, x-11=0

or, x=11

So, Width=x/10=11/10=1.1

Checking:

So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2

Area=Length*Width=11*1.1=12.1

Hence, Perimeter= 2 Area

As,24.2=2*12.1=24.2

So, Perimeter=2 Area

So, Answer:Length of Rectangle=11 units

Width of Rectangle=1.1 units

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3 years ago
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When x=1/4 x²=1/16 so f(1/4)=y=2 1/16 last answer
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Which statements are true of functions?
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Which statement regarding the interior and exterior angles of a triangle is always true?
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