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3 years ago

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Which inequality or inequalities have the same solution as 10≤x+4? 0≤x+14 6≤x 14≤x 0≤x−6

1 answer:

Anna007 [38]3 years ago

6 0

Answer:

6 ≤ x and 0 ≤ x - 6

Step-by-step explanation:

The original equation of inequality is 10 ≤ x + 4 ....... (1)

It gives 6 ≤ x or 0 ≤ x - 6

Therefore, 0 ≤ x + 14 does not mach with the inequality (1).

And the same solution will not be there for them.

Again, 14 ≤ x also does not match with inequality (1).

And the same solution will not be there for them.

Therefore, 6 ≤ x and 0 ≤ x - 6 gives the same solution as (1).

(Answer)

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A triangle has an area of 9m2 and a base of 6m. how do I find the height of this triangle?

KonstantinChe [14]

You know the triangle has a base of 6 meters, and that the formula to find the area of a triangle is 1/2bh or one-half of the base times the height. So, you would plug in 9 meters squared=one half of six times h, or 9m^2=1/2(6)*(h). In simplifying this, you would get 3h=9m^2. Divide both sides by three and get h=3. Hope this helps, and if you need any further explanations, please let me know!

8 0

3 years ago

Solve each equation by completing the square 2q^2+8q=3

3241004551 [841]

Answer:

Divide by 2

q^2+4q=3/2

q^2+4q(4/2)^2=3/2+(4/2)^2

(q+4/2)^2=3/2+16/4

taking the square root of both side

√(q+4/2)^2=√(3/2+16/4)

Note that the square will cancel the square root then you will take LCM on the right hand side

q+4/2=√6+16/4

q+4/2=√22/4

q= -4/2+-√22/4

q=(-4+_√22/4)

5 0

3 years ago

You accidentally dropped a coin from the top of 7 stairs. What is the probability that it will land below the sixth step and hea

Sergeeva-Olga [200]

1/7 * 1/2 = 1/14
1/2 because there is a 50/50% chance its either heads or tails

3 0

2 years ago

Read 2 more answers

Pls answer quick I will give brainliest

eimsori [14]

Answer:

EBC and CBF are supplementary.

EBD=66

Step-by-step explanation:

Since vertical angles are congruent, ABE=CBF

ABE=40-x

40-x + 6x-30=90

5x+10=90

5x=80

x=16

16(6)-30=66

6 0

3 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

So

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

So

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago