9.3 and
were closest to another.
<u><em>Explanation</em></u>
First we will convert each given fractions into decimal form. So....

Then the scores are: 9.30, 9.50, 9.80, 9.95 and 9.25
So, 9.30 and 9.25 are closest to another as their difference is (9.30-9.25)=0.05
That means , 9.3 and
were closest to another.
Answer:
itds the pint of the secletio
Step-by-step explanation:
(−5)(2)−2(−3)+3 ( -5 )( 2 ) - 2 ( -3 ) + 3
=-10+6-30+6+3
=15-40
=-25
Step-by-step explanation:
Break down every term into prime factors. ...
Look for factors that appear in every single term to determine the GCF. ...
Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...
Multiply out to simplify each term.
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)