Which situations can be simulated using this spinner? Select three options.
1 answer:
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Answer
Find out the original side length of the square .
To prove
Let us assume that the original length of the square be x.
Formula
As given
The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other.
Length becomes = x + 8
Breadth becomes = x -3
The area of the resulting rectangle is 126 in²
Put in the formula
(x + 8) × (x - 3) = 126
x² -3x + 8x -24 = 126
x ²+ 5x = 126 +24
x² + 5x - 150 = 0
x² + 15x - 10x - 150 = 0
x (x + 15) -10 (x +15) =0
(x + 15)(x -10) =0
Thus
x = -15 , 10
As x = -15 (Neglected this value because the side of the square cannot be negative.)
Therefore x = 10 inches be the original side of the square.
Answer: F
Step-by-step explanation:
This is basically like 2 rectangles. Find the area of both and add them together.
Remember that the area is x
.
Area of Rectangle 1: = 7,
= 14
14 x 7 = 98
Area of Rectangle 2: = 5,
= 14
14 x 5 = 70
Add the areas together: 98 + 70
= 168