Answer:
D. 9
Step-by-step explanation:
Let
abc=100a+10b+c
bca=100b+10c+a
cab=100c+10a+b
abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)
=100a + 10b + c + 100b + 10c + a + 100c + 10a + b
Collect like terms
=100a + a + 10a + 10b + 100b + b + c + 10c + 100c
=111a + 111b + 111 c
Factorise
=111(a+b+c)
abc + bca + cab = 111(a+b+c)
Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)
abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)
abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)
abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)
abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)
Answer:
It was approximately a 9% decrease. (If you need to round to the nearest tenth, 9.1. If you need to round to the nearest hundredth, 9.10).
Step-by-step explanation:
I am going to assume that the question means that Andrea could have earned 220 points on the assignment, but instead because the assignment was late, she was marked down 20 points. (Reduced to 20 points is kind of awkward wording).
Given that, 20 divided by 220 comes out to 0.0909 repeating.
0.09, as a percentage, is 9%. (Again, 0.0909, 9.09%, could be rounded up to 9.1%).
Hope this helps!
Answer:
Step-by-step explanation:
when multiplying two numbers with exponents that have the same base, you “combine” the numbers and just add the exponents
1) 3^2x3^4
3^6
2) 4^3x4^2
4^5
3) 2^3x2^2
2^5
4) 10^3x10^1
10^4
Any number as the denominator and 0 as the numerator can be replaced in the place of 0.
