Its just a matter of subbing...but keep in mind, for it to be a solution, it has to satisfy all 3 inequalities
x - y > = -4
2x - y < = 5
2y + x > 1
solutions are : (-1,3) and (3,5)
Rearrange the polynomial:
a^2–2ab+b^2 - c^2
((a-b)(a-b))-c^2
(a-b)^2-c^2
Set x =a-b and y=c. The formula becomes
x^2-y^2
factoring this polynomial, we get
(x+y)(x-y)
Substituting back, we get:
(a+b+c)(a+b-c)
Let’s multiply it out to check:
A^2 -ab ac
- ab B^2 -bc
-ac bc -c^2
Answer:
a = -49
Step-by-step explanation:
a+|-23+6|=-32
Simplify the absolute value term
a+|-17|=-32
a+17=-32
Subtract 17 from each side
a +17-17 = -32-17
a = -49
I think its the second one. So B. because its up 3 on the X-Axis and then the rest are wrong
