-2x+10
Leave a comment if any doubt
Answer:
Length of the shorter diagonal is 8.68 cm.
Step-by-step explanation:
Length of the side AB = 11 cm
Length of side BC = 5 cm
Angle between these sides, m∠ABC = 50°
By cosine rule in ΔABC,
AC² = AB² + BC² - 2AB.BC.cos B
AC² = (11)² + 5² - 2(11)(5)cos50°
AC² = 121 + 25 - 70.71
AC = √(75.29)
AC = 8.68 cm
By the property of parallelogram,
m∠B + m∠C = 180° [Interior consecutive angles]
50° + m∠C = 180°
m∠C = 130°
Similarly, In ΔBCD,
BD² = BC² + CD² - 2BC.CD.cos130°
BD² = (5)² + (11)² - 2(5)(11)cos130°
BD² = 25 + 121 + 70.71
BD² = 216.71
BD = 14.72 cm
Therefore, length of the shorter diagonal will be 14.72 cm.
Answer:
A=112 in. squared
Step-by-step explanation:
A=bxh=14·8=112
This question revolves around the concept of domain (primarily) and range (secondarily). The domain of the square root function is [0, +infinity).
The domain of "three times the sqrt of a" shares that domain: [0, +infinity).
We were not asked to come up with the range, but if the range is wanted, it is
[0, +infinity).