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AveGali [126]
2 years ago
9

Please help asap pre alg

Mathematics
1 answer:
algol [13]2 years ago
5 0

Answer:

the answer is c there bud

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Rewrite each fraction in simplest form using the GCF of the numerator and denominator.
Elanso [62]

Answer:

\sf 6. \quad \dfrac{7}{10}

\sf 7. \quad \dfrac{5}{17}

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 42 = 2 × 3 × 7
  • 60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF:  2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 80 = 2 × 2 × 2 × 2 × 5
  • 272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF:  2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}

5 0
1 year ago
Read 2 more answers
HELPPPP PLEASEEEEE !!!!!What is the surface area of the composite solid?
Bingel [31]

Answer: answer C is correct or 1,808 meters squared

Step-by-step explanation:

4 0
3 years ago
Help please thank you!
monitta

Answer:

• multiplied by 4p: (x -h)² +4pk = 0

• zeros for k > 0: none

• zeros for k = 0: one

• zeros for k < 0: two

Step-by-step explanation:

a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...

(x -h)² +4pk = 0

__

b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)

__

c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)

__

d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.

_____

The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.

8 0
3 years ago
How do you solve this?
natali 33 [55]
Not sure if you wanted answers or explanation on what to do. Ill just do the explanation and if you want the answers just lmk C:

R=1/2 d, and C=pi*2r. So you basically take the given number and plug it into these formulas.
7 0
2 years ago
Read 2 more answers
I need help with this problem
marishachu [46]

True

∠2 and ∠5 are both vertical at the vertex of the 2 straight lines



7 0
3 years ago
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