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aev [14]
3 years ago
10

Each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red

robins and 1 cardinal. What is the probability of a blue jay being the next bird papa sees?
Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

The answer to this is 0.421

Step-by-step explanation:

51/140=0.421


Y_Kistochka [10]3 years ago
7 0
The probability would be 59/140 or 42.14% (rounded: 42%).
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Dori and Malory are tracking their steps taken as a health goal. Dori leaves her house at 12:00 p.m. and walks at 50 steps per m
gladu [14]
Let n = minutes since 12:00 pm when Malory catches up to Dori.

Dori travels
(50 steps/min)*(n minutes) = 50n steps

Malory begins walking at 12:20 pm, so she walks for (n - 20) minutes. She travels
(90 steps/min)*(n - 20  min) = 90n - 1800 steps

Equate the steps traveled by Dori and Malory.
90n - 1800 = 50n
40n = 1800
n = 45 min

The time corresponding to n = 45 min is 12:45 pm

Answer: 12:45 pm

7 0
3 years ago
(-5,8) and (-10,3) what is the slope
ale4655 [162]

Answer:

The slope is 1.

Step-by-step explanation: when you graph them you do the rise/run you get 1 which is the slope.

4 0
3 years ago
Read 2 more answers
Evaluate. 75-2(9-5)²+2³
Andreyy89
75-2(9-5)^2+2^3

First, solve the parentheses:

75-2(4)^2+2^3

Next, the exponential terms

75-2(16)+8

Solve the multiplication:

75-32+8

Add and subtract:

51

5 0
1 year ago
Describe how you would use a yardstick to measure a rug
Dafna11 [192]
Well first of this makes sense because you need to make sure your rug will fit.  So anyways, first lay your rug out on a flat surface, grab your yardstick, lay it on the rug to find the length and then the width.  you then know the size of your rug(assuming its square).  You can do the same thing in the room you want it in.  
6 0
3 years ago
What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
3 years ago
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