Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:
Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:
2. Charlene's rhombus:
Dividing the area calculated, you get:
Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
Step-by-step explanation:
Use proportions to solve.
Corresponding sides have same ratio.
<u>Question 1</u>
- (6x + 3)/17 = (8x - 1)/21
- 21(6x + 3) = 17(8x - 1)
- 126x + 63 = 136x - 17
- 10x = 80
- x = 8
<u>Question 2</u>
- (x + 8)/21 = 32/28
- x + 8 = 21*8/7
- x + 8 = 24
- x = 24 - 8
- x = 16
Answer:
(1, 2)
Step-by-step explanation:
Given the equation of the lines x + 2y = 5 and 2x - 3y = -4
First we need to make x the subject of the formulas
For x+2y = 5
x = 5 - 2y ... 1
For 2x - 3y = -4
2x = -4+3y
x = (-4+3y)/2 ... 2
Equate 1 and 2
5 - 2y = (-4+3y)/2
2(5-2y) = -4+3y
10 - 4y = -4+3y
-4 -3y = -4-10
-7y = -14
y = 14/7
y = 2
Substitute y = 2 into 1
x = 5 = 2y
x = 5 - 2(2)
x = 5 - 4
x = 1
Hence the point where the lines meet will be at (1, 2)
