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3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. Show your work OR give an explaination.

Mathematics

1 answer:

alexandr402 [8]3 years ago

5 0

Answer:

Step-by-step explanation:

all of them are positive✔︎

all of them are real numbers✔︎

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The amount of paper that the copy shop used this month was a 25% increase of the amount of paper they used last month. What perc

likoan [24]

Answer:

You didn't include any image here, but numerically, the amount of paper consumed this month is 125% compared to last month.

If last month's consumption is represented by 4 equal shapes, then the current month's consumption will be 5 shapes.

If last month's consumption is represented by 8 equal shapes, then the current month's consumption will be 10 shapes.

this pattern keeps repeating.

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3 years ago

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rewona [7]

Answer:

Hiiiii

Step-by-step explanation:

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3 years ago

The dimensions of four rectangles are given below. Which has an area different from the area of each of the other three?

storchak [24]

To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

$Area = Length \times Width$

Rectangle (a)

$Area = 4x \times 4$

$Area = 16x$

Rectangle (b)

$Area = 11 \times x$

$Area = 11x$

Rectangle (c)

$Area = 2 \times 8x$

$Area = 16x$

Rectangle (d)

$Area = 16x \times 1$

$Area = 16x$

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

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2 years ago

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l

slamgirl [31]

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

5 0

3 years ago

The altitude of a triangle forms a perpendicular line. False True

Ksivusya [100]

True is the answer for this question

4 0

3 years ago