Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
Yes
Step-by-step explanation:
If they're perpendicular, that means that angle ECM = 90 degrees and angle ACE = 90 degrees. To figure out if this works, plug that into the two equations they give:
ECM = 3x + 15
becomes
90 = 3x + 15
75 = 3x
25 = x
ACE = 4x - 10
becomes
90 = 4x - 10
100 = 4x
25 = x
Since you get x = 25 for both, you know that they are perpendicular because they both measure 90 degrees
Wait I know u still need the answer or not anymore
Answer:
Step-by-step explanation:
N(106,14²)
(calculated using excel, let me know if you were supposed to use a normal table) = 0.4715
85.34
Q1:96.56
Q3:115.44
IQR (which is Q3-Q1)= 115.44-96.56= 18.88
