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VLD [36.1K]
2 years ago
11

The dimensions of four rectangles are given below. Which has an area different from the area of each of the other three?

Mathematics
1 answer:
storchak [24]2 years ago
7 0

To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

Area = Length \times Width

<u>Rectangle (a)</u>

Area = 4x \times 4

Area = 16x

<u>Rectangle (b)</u>

Area = 11 \times x

Area = 11x

<u>Rectangle (c)</u>

Area = 2 \times 8x

Area = 16x

<u>Rectangle (d)</u>

Area = 16x \times 1

Area = 16x

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

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