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VLD [36.1K]
2 years ago
11

The dimensions of four rectangles are given below. Which has an area different from the area of each of the other three?

Mathematics
1 answer:
storchak [24]2 years ago
7 0

To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

Area = Length \times Width

<u>Rectangle (a)</u>

Area = 4x \times 4

Area = 16x

<u>Rectangle (b)</u>

Area = 11 \times x

Area = 11x

<u>Rectangle (c)</u>

Area = 2 \times 8x

Area = 16x

<u>Rectangle (d)</u>

Area = 16x \times 1

Area = 16x

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

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3 friends share the cost of a gift. The gift costs $70, but the store manager takes $10 off the market price. What amount should
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Answer:

Amount each friend pays for the gift = $20

Step-by-step explanation:

Market price of a gift = $70

The store manager takes $10 off the market price.

Marked down amount = $10

New cost price = Marked price - Marked down amount =\$70-\$10=\$60

The cost of the gift is divided among three friends.

This means that the cost of gift which is $60 is divided by three to get each one's contribution in the gift.

∴ Amount each friend pays for the gift =\frac{60}{3}=\$20

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3 years ago
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2 years ago
Read 2 more answers
Help me please. 30 points :)
Nataly [62]

\frac{(5 \:  -  \: 8x)}{( \sqrt{5 \:  -  \: 8x} )}  \:  =  \:  \sqrt{5 \:  -  \: 8x}
For the result to be Real,
5 \:  -  \: 8x \:  \geqslant  \: 0
8x \:  \leqslant  \: 5
x \:  \leqslant  \:  \frac{5}{8}
( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \:  \times  \:  (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \:  =  \:  \frac{ {(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
Hence,
\frac{{(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
is the required form.

3 0
3 years ago
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