Find the x- and y-intercepts of 3x + 6y = 18
1 answer:
In order to find the x and y intercepts of an equation, you can plug in 0 for the opposite variable. Let us solve for the intercepts now.
<span>x-intercept
</span>We are going to plug in 0 for y and the solve for x:
So now we know the x-intercept of the line is: (6, 0)
<span>
y-intercept</span>
We are going to plug in 0 for x and solve for y:
So now we know that the y-intercept for the line is: (0, 3)
<span>x-intercept
</span>We are going to plug in 0 for y and the solve for x:
So now we know the x-intercept of the line is: (6, 0)
<span>
y-intercept</span>
We are going to plug in 0 for x and solve for y:
So now we know that the y-intercept for the line is: (0, 3)
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The graphs of f(x) and g(x) are transformed function from the function y = x^2
The set of inequalities do not have a solution
<h3>How to modify the graphs</h3>
From the graph, we have:
and
To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.
To derive y > x^2 + 2, we perform the following transformation on the function g(x)
- Shift the function g(x) down by 2 units
- Reflect across the x-axis
- Shift the function g(x) down by 3 units
- Change the equality sign in the function g(x) to greater than
The inequalities of the graphs become
y < x^2 - 3 and y > x^2 + 2
From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.
Hence, the set of inequalities do not have a solution
Read more about inequalities at:
