Answer:here
Step-by-step explanation:
Answer:
C) ![A+\frac{2}{5}B](https://tex.z-dn.net/?f=A%2B%5Cfrac%7B2%7D%7B5%7DB)
Step-by-step explanation:
Given Equations:
A) ![\frac{2}{5}x+y=12](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7Dx%2By%3D12)
B) ![\frac{5}{2}y-x=6](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7Dy-x%3D6)
In order to eliminate
we need to multiply
to equation B and add it to A.
Multiplying
to B.
⇒ ![\frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%5Ctimes%20%28%5Cfrac%7B5%7D%7B2%7Dy-x%29%3D%5Cfrac%7B2%7D%7B5%7D%5Ctimes%206)
⇒ ![(\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B5%7D%5Ctimes%5Cfrac%7B5%7D%7B2%7Dy%29-%28%5Cfrac%7B2%7D%7B5%7Dx%29%3D%5Cfrac%7B12%7D%7B5%7D)
⇒ ![y-\frac{2}{5}x=\frac{12}{5}](https://tex.z-dn.net/?f=y-%5Cfrac%7B2%7D%7B5%7Dx%3D%5Cfrac%7B12%7D%7B5%7D)
Adding it equation A.
![\frac{2}{5}x+y=12](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7Dx%2By%3D12)
+ ![-\frac{2}{5}x+y=\frac{12}{5}](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B5%7Dx%2By%3D%5Cfrac%7B12%7D%7B5%7D)
We get ![2y=\frac{72}{5}](https://tex.z-dn.net/?f=2y%3D%5Cfrac%7B72%7D%7B5%7D)
Thus
is eliminated.
So, the expression used to eliminate
is:
![A+\frac{2}{5}B](https://tex.z-dn.net/?f=A%2B%5Cfrac%7B2%7D%7B5%7DB)
9.32
if you really need to know why,
the .3 is greater than the .2,
and if you subtracted both numbers, the answer that gets you the positive difference is the larger number...
Answer:
yes 1/3 5 isb don't ehejdvduvrjdvdjrnrrjr didojdgovrodb
Yes it is.... it is heard to explane thow.... 1 second ill get it