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Flura [38]
3 years ago
14

What is the answer to x-5?

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer: x=5

Step-by-step explanation:

i’m not sure if that’s what you meant. there’s not much info.

Vladimir79 [104]3 years ago
6 0

x-5= 0

move -5 to the other side

sign changes from -5 to +5

x-5+5=0+5

x= 0+5

answer:

x= 5

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I think it’s 25.6 or not
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Emely has 25 onions and 14 peppers that she grew in her garden. homw many more oinons does she have that peppers
stiks02 [169]

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11

Step-by-step explanation:

<u><em>SUBTRACT</em></u>

4 0
3 years ago
0.2y=0.5x+0.1 please solve with math thank you
Cerrena [4.2K]
<span>"Simplifying 0.2y = 0.5x + 0.1
 Reorder the terms: 0.2y = 0.1 + 0.5x Solving 0.2y = 0.1 + 0.5x Solving for variable 'y'.
 Move all terms containing y to the left, all other terms to the right.  
Divide each side by '0.2'. y = 0.5 + 2.5x Simplifying y = 0.5 + 2.5x"</span>
7 0
3 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
5-2(x+5)=3x-15 solve for X
Maslowich

Answer:

x= 2

Step-by-step explanation:

5 -2(x +5)= 3x -15

Expand:

5 -2x -2(5)= 3x -15

5 -2x -10= 3x -15

Simplify:

-2x -5= 3x -15

Bring x terms to 1 side, constant to the other:

3x +2x= 15 -5

5x= 10

Divide both sides by 5:

x= 10 ÷5

x= 2

8 0
3 years ago
Read 2 more answers
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