Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.
Step-by-step explanation:
The interquartile range are resistant to outliers and can be used for data having glaring outliers.
Outliers are values that are too far away from the central value.
Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.
Answer:
4 1/2 + 1 3/5 = 6 1/10 or 61/10
Answer:
Answer: a5 = 2500
Step-by-step explanation:
For a geometric sequence:
First term = a0
Second term = a1 = a0*r
Third term = a2 = a0*r^2
Fourth term = a3 = a0*r^3
....
nth term = a(n-1) = a0*r^(n-1)
Given: a1 = 4 = a0*r
Also: r = 5
So, a0*5 = 4 => a0 = (4/5)
a5 = a(6-1) = Sixth term = a0*r^5 = (4/5)*5^5 = 2500
Hope this helps
correct me if im wrong☺
