HOW do you find the value of TAN 88 degrees 22' 45'' and COT 36 degrees???
1 answer:
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If a2 -2ab + b2 = 9 and a
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3If a2 -2ab + b2 = 9 and a
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3