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Lera25 [3.4K]
3 years ago
13

Please, can you give me help with answer #1- #2 and #3.Thanks.

Mathematics
2 answers:
Setler79 [48]3 years ago
8 0
1. radius r = 20 cm

area = pi*r^2 = 3,14*400 = 1256 cm^2

circumference = 2pir = 2*3,14*20 = 136 cm

2. radius = 8 cm 

area = 3,14*8^2 = 3,14*64 = 200,96 cm^2

circumference = 2*3,14*8 = 50,24 cm

3. radius = 1 cm 

area = 3,14*1^2 = 3,14*1 = 3,14 cm^2

circumference = 2pir = 2*3,14*1 = 6,28 cm

hope these will help you 
ad-work [718]3 years ago
4 0
Look at pic for work, all answers and work is listed

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The overall reliability is 99.7402 %

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The overall reliability of the product is calculated as the product of the working probability of the components.

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P(failure)=\frac{3}{10000}

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P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997

Finally, for components I and J :

P(failure)=\frac{5}{10000}

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P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

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Overall reliability = (0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402

0.997402 = 99.7402 %

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