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Anastaziya [24]
3 years ago
5

Is 4y=16x a Direct variation

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also

increases.

  • Yes, 4·y = 16·x is a direct variation

Reasons:

A direct variation is a relationship that exists between two variables. It is

also known as a direct proportion which can be expressed as; y = k·x

Where <em>k</em> is a number

The given equation is 4·y = 16·x

Dividing both sides by 4 gives;

\displaystyle \frac{4 \cdot y}{4}  = \frac{16 \cdot x}{4} = \frac{4 \times 4 \cdot x}{4}

Which gives;

y = 4·x

Comparing the above equation with the equation for a direct variation gives;

y = 4·x

y = k·x

Therefore;

k = 4

The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.

Learn more about direct variation here:

brainly.com/question/6499629

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4 years ago
Answers for 11,12,13
lisabon 2012 [21]
My picture for 11 shows how you would set that up. S is the midpoint meaning it is directly in the center so both sides will be equal.
5x+17=8x-31
48=3x
16=x
now put that in for the x in RS
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RS=97

12)
same as 11 but you have a picture already. if a line bisects it then it is cut into 2 equal parts.
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-3=x
put it in for both halves of AC
(4-5(-3))+(2(-3)+25)
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AC=38

13)
You can find DE by subtracting CD by CE (49)
since we already have CE we just have to find CD which is equal to AC which has been set up in the same way as 11 and 12 except now we'll have to set up the equation differently.
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