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3 years ago

You purchase a car using a $20,000 loan with a 5% simple interest rate.

Mathematics

1 answer:

Aliun [14]3 years ago

3 0

Answer: check out MATHPORTAL.com

Step-by-step explanation:

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3. MATCH is a regular pentagon with coordinates M(-1,1) and A(3,0). What is the perimeter of MATCH?

Makovka662 [10]

Answer:

<h3>2.squareroot 85</h3>

Step-by-step explanation:

<h2>#carry on learning</h2><h2>#mark branlits</h2>

6 0

2 years ago

You pack sandwiches for a mountain hike with your friends. each sandwich takes 2 slices of bread, and you pack 3 sandwiches for

Brrunno [24]

2*3n would be the equation.

6 0

2 years ago

Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $24 monthly fee

JulsSmile [24]

Answer:

600 minutes

Step-by-step explanation:

If we write both situations as an equation, we get:

y1 = 24 + 0.15x

y1 : total cost paid in first plan

x : total minutes of calls

y2 = 0.19x

y2 : total cost in second plan

x: total minutes of call

We are now looking for the situation where the total cost in the two plans is equal, so

y1 = y2

this gives

24 + 0.15x = 0.19x

<=> 0.04x = 24

<=> x = 600

7 0

2 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

2 years ago

What does the digit 7 represent in 170,280?

Sidana [21]

Answer:

that is the ten thousands place

Step-by-step explanation:

3 0

2 years ago