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Zigmanuir [339]
4 years ago
12

A child standing 15 feet from the base of a lamppost casts a shadow 5 feet long. If the child is 4 feet tall and walks towards t

he lamppost at a speed of 10 feet per minute, at what rate, in feet per minute, will the length of his shadow be changing?

Mathematics
1 answer:
Ber [7]4 years ago
3 0

Step-by-step explanation:

Below is an attachment containing the solution.

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I need this answer ASAP <br> Please do this for me I will mark as brainiest and I will give thanks
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4 years ago
What is 108 divided by 8
pantera1 [17]

Answer:

13.5

Step-by-step explanation:

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Or 13 with a remainder of 5

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3 0
3 years ago
Read 2 more answers
A rectangular field is 4 times as long as it is wide. If the length is decreased by 10 in. and the width is increased by 2in. th
Keith_Richards [23]
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5 0
3 years ago
HELP PLEASE <br><br><br> Simplify.
maksim [4K]
Simplifying
2x + -3(3 * 0.6x + 2.7)

Multiply 3 * 0.6
2x + -3(1.8x + 2.7)

Reorder the terms:
2x + -3(2.7 + 1.8x)
2x + (2.7 * -3 + 1.8x * -3)
2x + (-8.1 + -5.4x)

Reorder the terms:
-8.1 + 2x + -5.4x

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7 0
3 years ago
Find the zeros of the following expression x^2+5x+6 show all work
GaryK [48]
Let y = 0 to find the zeros.
x^{2} + 5x + 6 = 0

We can now split the middle term into factors of 6 that add up to 5.
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Group the first two terms, and group the last two terms, and factorise.
(x^{2} + 3x) + (2x + 6) = 0
x(x + 3) + 2(x + 3) = 0

Group like terms.
(x + 3)(x + 2) = 0

Now, we know that in order for a zero to occur, either x + 3 = 0 or x + 2 = 0.
Hence, x = -3 and -2 are the zeros in this quadratic.
8 0
4 years ago
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