Move each point 3 spaces to the right and connect the dots
Answer:
-12h^2-4+9-3h^2
Final result :
-5 • (3h^2 - 1)
Hope This Helps! Have A Nice Day!!
Answer:
y = 4x + 9/4
Step-by-step explanation:
4x − y − 3 = 0
y = 4x − 3
The slope of the line is 4.
The slope of the tangent line is:
f(x) = x − x²
f'(x) = 1 − 2x
Setting the slope equal to 4:
4 = 1 − 2x
2x = -3
x = -3/2
The point on f(x) is:
f(-3/2) = -3/2 − (-3/2)²
f(-3/2) = -3/2 − 9/4
f(-3/2) = -15/4
Using point-slope form:
y − (-15/4) = 4 (x − (-3/2))
y + 15/4 = 4 (x + 3/2)
y + 15/4 = 4x + 6
y = 4x + 9/4
Answer:
The launch angle should be adjusted to 30.63°
Step-by-step explanation:
The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;
R =(v^2 sin2θ)/g
Where
R = range
v = initial speed
θ = launch angle
g = acceleration due to gravity
For the case above. When the projectile is launched at angle 13° above the horizontal.
θ1 = 13
R1 = (v^2 sin2θ1)/g
R1 = (v^2 sin26°)/g ....1
For the range to double
R2 = (v^2 sin2θ)/g .....2
R2 = 2R1
Substituting R2 and R1
(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g
Divide both sides by v^2/g
sin2θ = 2sin26
2θ = sininverse(2sin26)
θ = sininverse(2sin26)/2
θ = 30.63°
