What is 1.44 divided by 0.4

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

00:00

OLEGan [10]

The answer is maybe C lol

4 0

4 years ago

On the first day in each month, Enid deposited $4 into her bank account and Jim deposited $3 into his. They opened these account

ohaa [14]

Answer:

The amount of money in Enid bank account can be written as a linear equation.

Ye = Xe + $4*m

where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.

For Jim, the equation is similar:

Yj = Xj + $3*m

where Yj and Xj are similar as above.

Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).

Then we have that:

Ye = $72 = Xe + $4*7 = Xe + $28

Xe = $72 - $28 = $44

So in May 15, Enid deposited $44.

For Jim we have:

Yj = $72 = Xj + $3*7 = Xj + $21

Xj = $72 - $21 = $51

So in May 15, Jim deposited $51.

5 0

3 years ago

Which value of v is a solution to this equation? 3v=24

zhannawk [14.2K]

V = 24/3 = 8
So v = 8
Hope this helps, if it is , pls brainliest !!

6 0

3 years ago

Read 2 more answers

Which board geometrically represents 4x2 – 1 using algebra tiles? An algebra tile configuration showing only the product spot, w

NemiM [27]

An algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

The correct option is B.

Given

Equation; $\rm 4x^2 - 1$

<h3>Quadratic equation</h3>

It is a polynomial that is equal to zero.

Polynomial of variable power 2, 1, and 0 terms are there.

Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

4x² -1 = 0 is a quadratic equation.

An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

Then,

The factors of the polynomial is;

$\rm 4x^2 - 1=0\\\\ 4x^2-2x+2x-1=0\\\\ 2x(2x-1)+1(2x-1)=0\\\\(2x-1)(2x+1)=0$

Hence, an algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

More about the quadratic equation link is given below.

brainly.com/question/2263981

7 0

2 years ago