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3 years ago

What is 1.44 divided by 0.4

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

The quotient to 1.44 and 0.4 equals to 3.6

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3) determine the value of (-6) x (-3)

Serhud [2]

-6 × -3
- × - = +
6×3 = 18

= 18

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3 years ago

This semicircle has a diameter of 5 m.

Mumz [18]

3.93 is the correct answer.
I hope this helps.

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4 years ago

Read 2 more answers

When will the distance from A to B be negative?

Aneli [31]

The distance from A to B will be negative when the line is trending downward from left to right.

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3 years ago

The distance an airplane travels depends on how much time it spends flying. Which expression represents the distance the airplan

kogti [31]

Answer: B. $\text{Distance(20)}$

Step-by-step explanation:

The notation to express a dependent variable is given by :-

$Y(x)$ , where Y is depending variable which is dependent upon x ( independent variable).

The given statement : The distance an airplane travels depends on how much time it spends flying.

Here , Independent variable : Time

Dependent variable : Distance

Then , the notation to express distance (dependent variable) the airplane flies in 20 minutes is given by :-

$\text{Distance(20)}$

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3 years ago

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

Darya [45]

Answer:

A=3 and B=6

Step-by-step explanation:

Increasing and Decreasing Intervals of Functions

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

$f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9$

Computing the first derivative:

$f' ( x ) = - 6 x^3 + 54 x - 108$

We find the critical points equating f'(x) to zero

$- 6 x^3 + 54 x - 108=0$

Simplifying by -6

$x^2 -9 x +18=0$

We get the critical points

$x=3,\ x=6$

They define the following intervals

$(-\infty,3),\ (3,6),\ (6,+\infty)$

Thus A=3 and B=6

3 0

3 years ago