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AURORKA [14]
3 years ago
13

Mark earned $48. He spent $6 and saved the remaining money.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

1:7

Step-by-step explanation:

You might be interested in
Is (x-3) a factor of f(x) = x^2 - 32?
Leokris [45]

Answer:

No

Explanation:

Here, we want to use the factor theorem to check if the given linear expression is a factor of the binomial

Now, according to the factor theorem, a factor of a polynomial would leave no remainder when divided by it

Mathematically, it means when we substitute the factor value into the polynomial, it is expected that the remainder is zero is the substituted is a factor of the polynomial

We set x-2 to zero:

\begin{gathered} \text{ x-2 = 0} \\ x\text{ = 2} \end{gathered}

Now, we substitute 2 into the polynomial as follows:

f(2)\text{ = }2^2-32\text{ = 4-32 = -28}

There is a remainder of -28 and thus, the linear factor is not a factor of the binomial

3 0
1 year ago
I need help asap!! <br> if p= -1, 5 Rx axis (P)
Evgesh-ka [11]

Answer:

P'(7, 5)

Step-by-step explanation:

Rule for the transformation of a point R_{x=1}(P) defines,

Reflection of a point P(x, y) about a line, x = 1 which is parallel to y-axis.

Line x = 1 works like a mirror so the distance between the line and the image point will be equal to the distance between the line and the original point.

Distance between the line and a point (-1, 5) = 4

Therefore, distance between the line and the image point = 4

Coordinates of the image point will be,

P'(3, 5)

7 0
3 years ago
Find the missing term of 3b2 − = -9b2 ?<br> -6b^2<br> -9b^2<br> -12b^2
gladu [14]
3b^2 - x = -9b^2 
x = 3b^2 +9b^2

x = 12b^2

3b^2 -12b^2 = -9b^2

hope this will help you 
7 0
3 years ago
Please help me with this for brainliest <br><br><br><br> also whats yalls insta i might add you
seraphim [82]

Answer:

9

Step-by-step explanation:

divied by 3

27  divided by 3 is 9

plz mark brainliest

4 0
3 years ago
Factor 16b^2 - 40b +25
WINSTONCH [101]
Your answer will be,

ANSWER: (4b - 5)^2

You're welcome :)
4 0
3 years ago
Read 2 more answers
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