Is (0,0) a solution to this system?

Mathematics

1 answer:

galina1969 [7]3 years ago

8 0

The answer is A because if you plug in the coordinates (0,0) into y<x^2+2x+1 you get....0<1+2+1. Which simplified is 0<4. For the other equation if you plug in (0,0) you'd get 0≤-3 which is false.

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First you want to know what y or x is i chose y for this on

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$D:x^2-4\not=0\\
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